# KPK Board 10th Class Math Ch 1 Quadratic Equation Short Questions Answers

## KPK Board 10th Class Math Ch 1 Quadratic Equation Short Questions Answers

We are providing all Students from 5th class to master level all exams preparation in free of cost. Now we have another milestone achieved, providing all School level students to the point and exam oriented preparation question answers for all science and arts students.

After Online tests for all subjects now it’s time to prepare the next level for KPK board students to prepare their short question section here. We have a complete collection of all classes subject wise and chapter wise thousands questions with the right answer for easy understanding.

We provided 10th class Mathematics short questions answers on this page of all KPK boards. Students of KPK boards can prepare the Mathematics subject for annual examinations.

In this List we have included all KPK boards and both Arts and Science students. These Boards students can prepare their exam easily with these short question answer section

Malakand Board 10th classes short questions Answer

Mardan Board 10th classes short questions Answer

Peshawar Board 10th classes short questions Answer

Swat Board 10th classes short questions Answer

Dera Ismail Khan Board 10th classes short questions Answer

Kohat Board 10th classes short questions Answer

Abbottabad Board 10th classes short questions Answer

Bannu Board 10th classes short questions Answer

All above mention KPK Boards students prepare their annual and classes test from these online test and Short question answer series. In coming days we have many other plans to provide all kinds of other preparation on our Gotest website.

to Prepare KPK Board Classes Short Question Answer at Gotest

Just Open the desired Class and subject which you want to prepare.

You have Green bars which are Questions of that subject Chapter. Just click on Bar, it slides down and you can get the right answer to those questions.

^{4}– 5w

^{2}+ 2 = 0

Solution: 2x^{4} – 5w^{2} + 2 = 0……………..(i)

Let w^{2}= x ……….(ii) Then w^{4} w^{2}…………. (iii)

Put (ii) , (iii) , in (i)

2x^{2} – 5w + 2 = 0

=> 2x^{2} – 4x – x + 2 = 0

=> 2x ( x – 2 ) – 1 ( x-2) = 0

=> ( x-2 ) (2x – 1) = 0

=> x- 2 = 0 or 2x – 1 = 0

=> x= 2 or 2x = 1

=> x = 1/2

Put x = 2 in (ii) => w^{2} = 2 take square root

=> **√**w^{2} = __+__**√**2 => w = __+__**√**2

Put x = ½ in (ii) => w^{2} = ½ take square root

=> **√**w^{2} = __+__**√**½ => w = __+__**√**½ = __+__ 1/**√**2

Solution set = {__+__**√**2 = __+__ 1/**√**2}

ax^{2 }+ bx + 2 = 0

Solution ax^{2 }+ bx + 2 = 0 ……..….(i)

Put x = -1 in (i) => a(-1)^{2}+ b ( -1 ) + 2 = 0

=> a – b + 2 = 0 ………………(iii)

Put x = 1 in (i) => a(1)^{2}+ b (1)+ 2=0

=> a + b + 2 = 0 (iv)

Adding (iii) and (iv)

a – b + 2 = 0

(a+b+2=0)/(2a+4=0)

=> 2a = – 4 => a = – 4/2

=> 2a = -4 => a = -4/2

=> a = -2 put a = -2 in (iv)

=> – 2 + b + 2 = 0 => b = 0

Thus a = – 2 , b = 0 Ans.

^{2}+ 5x + 6 = 0 and x

^{2}+ 19x + 34 = 0 are equal.

Solution: Since x^{2}+ 5x+6=0 and x^{2}+ 19x+34 =0 are equal.

Then x^{2}+ 5x+6 = x^{2}+ 19x+34

=> x^{2}+x^{2}+ 5x-19=34- 6=0

=> – 14 x = 28 => x= -28/14

=> x = -2 Ans.

49x^{^2}- 316+123=0

Solution: 49x^{2}– 316+123=0

=> 49x^{2}– 294x-22x+123=0

=> 49x (x-6)-22(x – 6 )=0

=> (x-6) (49x -22)=0

=> (x-6) =0 or 49x -22=0

=> x = 6 or 49x = 22

=> x= 22/49

=> Thus solution set = { 6 , 22/49 }