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After Online tests for all subjects now it’s time to prepare the next level for Punjab board students to prepare their short question section here. We have a complete collection of all classes subject wise and chapter wise thousands questions with the right answer for easy understanding.
Here we are providing complete chapter wise Math questions and Answers for the 9th class students. All the visitors can prepare for their 9th class examination by attempting below given question answers.
In this List we have included all Punjab boards and both Arts and Science students. These Boards students can prepare their exam easily with these short question answer section
Lahore Board 9th classes short questions Answer
Rawalpindi Board 9th classes short questions Answer
Gujranwala Board 9th classes short questions Answer
Multan Board 9th classes short questions Answer
Sargodha Board 9th classes short questions Answer
Faisalabad Board 9th classes short questions Answer
Sahiwal Board 9th classes short questions Answer
DG Khan Board 9th classes short questions Answer
Bahwalpur Board 9th classes short questions Answer
All above mention Punjab Boards students prepare their annual and classes test from these online test and Short question answer series. In coming days we have many other plans to provide all kinds of other preparation on our Gotest website.
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9th Class Math Chapter 14 Ratio & Proportions Short Questions Answer
The ratio of two quantities a and b of same kind is denoted as a:b and is defined as: The ratio a:b = a/b is the Comparison of two like a and b quantities ‘a’ and ‘b’ are called terms of ‘a’ ratio ‘b’. Terms must be expressed in the same units.
The statement of equality of two ratios is called proportion i.e. if a:b = c:d then a, b, c and d are said to be in proportion.
Two triangles said to be congruent written symbolically as≅, if there exists a correspondence between them such that all the corresponding sides and angles are congruent.
if AB≅ DE A≅ ∠D
BC≅EF and B≅∠E
Then ∆ABC ≅ ∆DEF
If in ∆ABC ↔ ∆DEF
∠A ≅D, ∠B ≅ ∠E, ∠C ≅ ∠F
and AB/DE = BC/EF = CA/FD
Then ∆ABC and ∆DEF are called a similar triangle which is symbolically written as ∆ABC – ∆DEF.
If m LM = 5cm, mLP = 2.5cm, m LQ = 2.3cm, m LN = ?
As PQ ‖ MN
mLP/mLM = mLQ/mLN
2.5/5 = 2.3/mLN
2.5(mLN) = 2.3 x 5 = 11.5
mLN = 11.5/2.5 = 115/25 = 23/5 = 4.6cm
If mLM = 6cm, m LQ = 2.5cm, mQN = 5cm, m LP = ?
As PQ ‖ MN
mLP/mLM = mLQ/mLN
mLP/6 = 2.5/7.2
mLP/6 = 2.5/7.5 x 6 = 25/75 x 6 = 2cm
mPA = 8x – 7, mPB = 4x – 3
mAQ = 5x – 3, m BR = 3x – 1
As AB ‖ QR
mPA/mAQ = mPB/mBR
8x–7/5x–23 = 4x–3/3x–1
(8x–7)(3x–1) = (4x–3)/(5x–3)
24x² – 8x – 21x + 7 = 20x² – 12x – 15x + 9
24x² – 20x² – 29x + 27x + 7 = 9
4x² – 2x + 7 = 9
4x² – 2x – 2 = 0
2x² – x – 1 = 0
2x² – 2x + x – 1 = 0
2x (x – 1) + (x – 1) = 0
(x – 1) (2x + 1) = 0
(x = 1, – ½ )
x = 1 is the required value.
mLN = 4, mLM = 6, mMN = 8
LA bisects ∠L
mMA/mNA = mLM/mLN = 6/4
i.e. mMA : mNA = 6:4
but mMN : mMA + mAN = 8
mMA = 6/10 x 8 = 48/10 = 4.8
and mAN = 4/10 x 8 = 32/10 = 3.2
PQ ≅ PR
⟹ x = 10cm
PM ? QR Where PQR is an isosceles triangle
∴ mMQ = mMR
⟹ y = 6cm