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After Online tests for all subjects now it’s time to prepare the next level for Punjab board students to prepare their short question section here. We have a complete collection of all classes subject wise and chapter wise thousands questions with the right answer for easy understanding.
Here we are providing complete chapter wise Math questions and Answers for the 9th class students. All the visitors can prepare for their 9th class examination by attempting below given question answers.
In this List we have included all Punjab boards and both Arts and Science students. These Boards students can prepare their exam easily with these short question answer section
Lahore Board 9th classes short questions Answer
Rawalpindi Board 9th classes short questions Answer
Gujranwala Board 9th classes short questions Answer
Multan Board 9th classes short questions Answer
Sargodha Board 9th classes short questions Answer
Faisalabad Board 9th classes short questions Answer
Sahiwal Board 9th classes short questions Answer
DG Khan Board 9th classes short questions Answer
Bahwalpur Board 9th classes short questions Answer
All above mention Punjab Boards students prepare their annual and classes test from these online test and Short question answer series. In coming days we have many other plans to provide all kinds of other preparation on our Gotest website.
How to Prepare Punjab Board Classes Short Question Answer at Gotest
- Just Open the desired Class and subject which you want to prepare.
- You have Green bars which are Questions of that subject Chapter. Just click on Bar, it slides down and you can get the right answer to those questions.
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Now you can start your preparation here below
9th Class Math Chapter 12 Line Bisectors and Angle Bisectors Short Questions Answer
Bisector of a line segment:
A line passing through the midpoint of a segment is called the bisector of line segment.
Bisector of an angle:
A ray that bisects an angle is called bisector of the angle.
∆ABC is equilateral
m∠A = m∠B = m∠C = 60°
∴∠° = 60°
AD is bisector of A
x° = y° = m∠A
= ½ (60°) = 30°
x° = y° = 30°
Corresponding sides of congruent triangles ∆LMO and ∆LNO.
LM ≅ LN
∴ 2x + 6 = 18
⟹ 2x = 18 – 6 = 12
x = 12/2 = 6
Given that mON = 12
Since given triangles are congruent therefore mOM = mON = 12
mOM = m = 12
If m AB = 6 cm, then find the m AL and m LB
If m BD = 4 cm, then find the m AD
CD is right bisector
∴ AL ≅ BL
∴ mAL = mBL
= ½ m AB = ½ (6cm) = 3cm
m AL = m BL = 3cm
In ∆ALD ↔ ∆BLD
AL ≅ BL
and DL ≅ DL
∆ALD ≅ ∆BLD
So, m AD ≅ m BQ = 4cm
m AD = 4cm