# 11th Class Physics Chapter 2 Vectors And Equilibrium Short Question Answers

## 11th Class Physics Chapter 2 Vectors And Equilibrium Short Question Answers Below

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C

^{→}=A

^{→}+B

^{→ }[ C

^{→}]=[ A

^{→}]=[ B

^{→}]

where modulus [ C

^{→}],[ A

^{→}],[ B

^{→}] indicate the magnitudes of vector C

^{→},A

^{→},B

^{→ }respectively.

Hence the maximum value of magnitude of component can be equal to the magnitude of the resultant vector.

^{→}makes an angle of 45ᵒ with horizontal axis (x-axis) the magnitude of the rectangular components will be

A

_{x}=A cos0=Acos45ᵒ

= A×0.707

or A

_{x}=0.707 A…………..(i)

and

A

_{y}=Asin45ᵒ = A×0.707

or A

_{y}=0.707 A…………… (ii)

Equations (i) and (ii) show that a vector will have components of equal magnitude if it makes an angle of 45ᵒ with x-axis

If the vectors A

^{→ }B

^{→},C

^{→},D

^{→},and E

^{→}are represented by the sides of a closed polygon then they are added by using head to tail rule.Thus the sun will be zero because the tail of the first vector coincides with the head of last vector

Hence,

A

^{→}+ B

^{→}+C

^{→}+D

^{→}+ E

^{→}n =0

Hence the sum of vectors of closed polygon becomes zero because their resultant is represented in magnitude and direction by the closing side of the polygon taken in opposite order.

^{→}

_{1 }and A

^{→}

_{2 }were reversed how would this alter A

^{→}

_{1 }A

^{→}?

^{→}

_{1 }and – A

^{→}

_{2 }are reversed then both these vectors will be written as – A

^{→}

_{1 }and A

^{→}

_{2 }. Therefore,

Their cross product= – A

^{→}

_{1 }A

^{→}

_{2 }= A

^{→}

_{1 }A

^{→}

_{2 }

Hence the vector product of two vectors will remain unchanged even by reversing all the components of vectors.

sin(o)n Thus A→× B→ = 0……… (1) And A→× B→= Absin180ᵒ n A→× B→ = Absin (0)n or A→× B→ = 0…………….(2) From equation (1) and (2) it is concluded that two vectors A→and B→, are parallel or anti-parallel to each other.

^{→}

_{1}and other F

^{→}

_{2 }.

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