KPK 11th Class Chemistry Chapter 12 Electrochemistry Short Questions Answers
KPK 11th Class Chemistry Chapter 12 Electrochemistry Short Questions with answers are combined for all 11th class(Intermediate/hssc) Level students.Here You can prepare all Chemistry Chapter 12 Electrochemistry short question in unique way and also attempt quiz related to this chapter. Just Click on Short Question and below Answer automatically shown. After each question you can give like/dislike to tell other students how its useful for each.
Class/Subject: 11th Class Chemistry
Chapter Name: Electrochemistry
Board: All KPK Boards
- Malakand Board 11th Class Chemistry Chapter 12 Electrochemistry short questions Answer
- Mardan Board 11th Class Chemistry Chapter 12 Electrochemistry short questions Answer
- Peshawar Board 11th Class Chemistry Chapter 12 Electrochemistry short questions Answer
- Swat Board 11th Class Chemistry Chapter 12 Electrochemistry short questions Answer
- Dera Ismail Khan Board 11th Class Chemistry Chapter 12 Electrochemistry short questions Answer
- Kohat Board 11th Class Chemistry Chapter 12 Electrochemistry short questions Answer
- Abbottabad Board 11th Class Chemistry Chapter 12 Electrochemistry short questions Answer
- Bannu Board 11th Class Chemistry Chapter 12 Electrochemistry short questions Answer
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KPK 11th Class Chemistry Chapter 12 Electrochemistry Short Questions Answers
KMnO4 + H2S + H2SO4 → K2SO4 + MnSO4 + S +H2O
+1+7-8 +2-2 +2+6-8 +1-1 +2-2 o+2 -2
KMnO4 + H2S + H2SO4 → K2SO4 + MnSO4 + S +H2O
+7 Mn Mn → Reduced ( gain of electron =5)
-2 S+7 → Oxidized (loss of electron =2)
Equalize the loss and gain by multiplying with the least possible figure.
Loss of electron = gain of electron
2 x 5 5 x 2
Multiply these figures with the corresponding elements in the equation.
2KMnO4+5H2S+H2SO4 → K2SO4+2MnSO4+5S+H2O
Balance the rest of the equation by inspection method.
2KMnO4+5H2S+3H2SO4 → K2SO4+2MnSO4+5S+8H2O
0 +6-6 +6-6 +2-2
Fe + V2O2 → Fe2O3+ VO
Fe → Fe3+( oxidized) loss of electron =3
V3+ → V2+reduced) gain of electrons =1
Total loss of electron=Total gain of electron 3×1= 1×3
Fe +3V2O3 → Fe2O3+ 3VO
2Fe +3V2O3 → Fe2O3+6VO
+4-4 +1-1 + 2 – 2 0 +2-2
MnO2+HCl → MnCl2+ Cl2+H2O
Mn+4 → Mn+2 Reduced (gain of electron =2)
2Cl- → Cl2 Oxidized (loss of electron =2)
Equalize the loss and gain of electrons by multiplying with the least possible figure.
Loss of electron = gain of electron
2 x 1 2 x 1
Multiply these figure with the corresponding elements in the equation. These is no need
MnO2 + HCl → MnCl2 + Cl2 + H2O
Balanced the rest of the equation by inspection method.
MnO2 + 4HCl → MnCl2 + Cl2 + 2H2O
KMnO4 + KNO2+ H2SO4 → MnSO4 + H2O+ KNO2K2SO4 Mn7+ → Mn2+(reduced) gain of electron =5 N3+ → N5+ (oxidized) loss of electron = 2 Loss of electron =Gain of electron 2 x 5 5 x 2 2KMnO4+ 5KNO2+ H2SO4 → 2MnSO4+H2O+5KNO3+K2SO4 2KMnO4+ 5KNO2+ 3H2SO4 → 2MnSO4+3H2O +5KNO3+K2SO4 0 + 1 – 1 + 2 – 2 0
Mg° → Mg2+ (oxidized) loss of e– =2 2M+1 → H2 (reduced) total gain of e– = 2 Loss of electron = gain of electrons 2 x 1 = 2 x 1 Mg + 2HCl → MgCl2 + H2
Cu + H2SO4 → CuSO4 + SO2+H2O
O + 2 + 6 – 8 + 2 – 2 + 4 – 4 + 2 – 2
Cu + H2SO4 → CuSO4+ SO2+H2O
Cu° → Cu+2 (Oxidized) loss of electron = 2
S+6 → S+4 (Reduced) gain of electron = 2
Loss of electron = gain of electron
2 x 1 = 2 x 1
Multiple these figures with the corresponding elements in the equation there is no need.
Cu + H2SO4 → CuSO4+ SO2+H2O
SO2+2H2
Balanced the rest of the equation by inspection method.
Cu + H2SO4 → CuSO4+ SO2+H2O
SO2+2H2
