KPK 11th Class Chemistry Chapter 11 Thermochemistry Short Questions Answers
KPK 11th Class Chemistry Chapter 11 Thermochemistry Short Questions with answers are combined for all 11th class(Intermediate/hssc) Level students.Here You can prepare all Chemistry Chapter 11 Thermochemistry short question in unique way and also attempt quiz related to this chapter. Just Click on Short Question and below Answer automatically shown. After each question you can give like/dislike to tell other students how its useful for each.
Class/Subject: 11th Class Chemistry
Chapter Name: Thermochemistry
Board: All KPK Boards
- Malakand Board 11th Class Chemistry Chapter 11 Thermochemistry short questions Answer
- Mardan Board 11th Class Chemistry Chapter 11 Thermochemistry short questions Answer
- Peshawar Board 11th Class Chemistry Chapter 11 Thermochemistry short questions Answer
- Swat Board 11th Class Chemistry Chapter 11 Thermochemistry short questions Answer
- Dera Ismail Khan Board 11th Class Chemistry Chapter 11 Thermochemistry short questions Answer
- Kohat Board 11th Class Chemistry Chapter 11 Thermochemistry short questions Answer
- Abbottabad Board 11th Class Chemistry Chapter 11 Thermochemistry short questions Answer
- Bannu Board 11th Class Chemistry Chapter 11 Thermochemistry short questions Answer
Helpful For:
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KPK 11th Class Chemistry Chapter 11 Thermochemistry Short Questions Answers
Reversing equation 2 and then solving equation no. 1 and three simultaneously
- H2(g) + I2(s) 2HI(g) ∆H°=51.8 kjmol-1 Rq No.1….
- H2(g) + H2(g) I2(g)∆H°=-10.5 kjmol-1Eq .No 3…
I2(s) I2(g)∆H°=sub=62.3 KJmol-1
HCL(g)+ aq HCl (aq) ∆H° =-72.41 KJ mol-1
NH3(ag) +HCl (aq) NH4Cl(aq)∆H° =-51.48 KJ mol-1
Solving all the three equation simultaneously. We get
NH3(ag)+ HCl(aq) NH4Cl(aq)∆H° =-159.05 kJ mol-1
C2H5OH(1)+ 3O2 → 2CO2(g)+3H2(g)∆ H10 =-1402.14KJ/mole
Eq.no.1
C(s)+O2(g) → CO2(g)∆H20 =-393.7KJ/mole
Eq.no.2
H2(g) +1/2 O2(g) → H2O(1) ∆H30 =-285.81 KJ/mole
Eq.no.3
This law is merely the law of conservation of energy i.e. the total amount of energy of the universe is constant however; energy can be transformed from one form to another.
Both heat and work are the form of energy. So the change in internal is equal to the sum of its heat changes and work. Thus the first law of thermodynamics can be written mathermatically as:
∆E = q + w
Where as ∆E =change in internal energy
Q = heat evolved or absorbed
W = work done
